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(C) The reaction sequence is as follows:$1$. $CaC_2 + 2H_2O \rightarrow HC \equiv CH (A) + Ca(OH)_2$$2$. $HC \equiv CH + H_2O \xrightarrow{Hg^{2+}, di

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$C_2H_5OH$

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(C) The reaction sequence is as follows:$1$. $CaC_2 + 2H_2O \rightarrow HC \equiv CH (A) + Ca(OH)_2$$2$. $HC \equiv CH + H_2O \xrightarrow{Hg^{2+}, dil. H_2SO_4} CH_3CHO (B)$ (Kucherov reaction)$3$. $CH_3CHO + H_2 \xrightarrow{Ni} CH_3CH_2OH (C)$ (Reduction of acetaldehyde to ethanol).Therefore,the end product $C$ is $C_2H_5OH$.

What is the end product of the following sequence of operations?
$CaC_2$ $\xrightarrow{H_2O} A$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} B$ $\xrightarrow[H_2]{Ni} C$

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What is the end product of the following sequence of operations?$CaC_2$ $\xrightarrow{H_2O} A$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} B$ $\xrightarrow[H_2]{Ni} C$